python + list + sort != true

[nauman]

will bring this question up again.

coding an application where i put information into a list(language python).
but before i really put the information into the list i would like to sort it in another way then just the "append" way.
Since every item will be put last into the list i would really like to order it by A-Z or Z-A or whatever.
i tried(written from my head):

items = ListItems()
item.Label("test")
items.append(item)

items.sort()
sorted(items, key=attrgetter('GetLabel'))

but none of the 2 last entries will successfully change the order of the list.
Does anyone know any way to sort the items in other way then the "append"-way?

can also say that neither items.insert(item, 0) work :S. kind of wierd since its included in pyhon 2.4

[jwilson11]

import operators
list = []
#add a bunch of stuff to the list - list.append(("jwilson11",29))
list.sort(key=operator.itemgetter(1))
#this will sort by the 2nd item in your tuple, in this case age
#then you can just loop your list and add the items to your boxee list
uilist = mc.ListItems()
for i in list:
item = mc.ListItem(mc.ListItem.TYPE)
item.SetLabel(i[0] + ' ' + i[1])
uilist.append(item)
mc.GetActiveWindow().GetList(9000).SetItems(uilist )


didn't try any of that as I am at work, but I think it should work

[nauman]

ah, so basically you making an array for all info you need and then but it into diffrent subarrays to listitems.

will try it in a min and see

[nauman]

thanks a bunch.. works great, feeling kinda stupid not thinking "out-side-the-box"

[jwilson11]

No problem, glad it worked for you